engineering · rotating-equipment-drives · compressors

Ideal Gas Compressor Power Discharge Temperature Calculator

Computes isentropic discharge temperature, specific work and shaft power for an ideal gas from the pressure ratio and the heat capacity ratio, either on the ideal isentropic branch or adjusted for an entered isentropic efficiency. Gas properties stay user inputs; it is a thermodynamic screen, not a compressor selection or a real-gas calculation.

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Calculator overview

Inputs and outputs

This summary comes from the calculator's published input and output contract.

Inputs

IGC Mass Flow Rate
About this input

Nonnegative gas mass flow. Zero is accepted and returns zero shaft power while retaining per-mass temperature and work results.

Unit kg/s Default 2.347 Range At least 0
IGC Isentropic Efficiency Conditional
About this input

Dimensionless efficiency greater than zero and no greater than one, used only for the Efficiency-adjusted model. Hidden values are inert in the ideal branch.

Unit fraction Default 0.817 Range 0 to 1
IGC Unit System
About this input

Select coherent SI or U.S. customary inputs and outputs. Changing the selector does not automatically convert values already entered.

Default SI metric Allowed SI metric, US customary
IGC Specific Heat Cp
About this input

Positive user-entered constant-pressure specific heat on the selected unit basis. The synthetic shipped value is not a property-table lookup.

Unit kJ/(kg*K) Default 1.0137 Range At least 0
IGC Inlet Temperature
About this input

Inlet gas temperature strictly above absolute zero. It is converted internally to kelvin before applying the isentropic temperature ratio.

Unit deg C Default 26.4 Range At least -273.15 (conditional)
IGC Discharge Absolute Pressure
About this input

Positive absolute discharge pressure at least as large as inlet pressure. Equality produces a transparent no-compression CHECK state.

Unit kPa absolute Default 493.7 Range At least 0
IGC Compression Model
About this input

Choose the ideal isentropic relation alone or apply a visible user-entered isentropic efficiency to work and temperature rise.

Default Efficiency-adjusted Allowed Ideal isentropic, Efficiency-adjusted
IGC Inlet Absolute Pressure
About this input

Positive absolute inlet pressure. Gauge pressure is not accepted because the ideal-gas pressure ratio requires absolute values.

Unit kPa absolute Default 117.3 Range At least 0
IGC Heat Capacity Ratio
About this input

User-entered dimensionless ratio cp/cv strictly greater than one. The workbook does not infer gamma from gas identity or temperature.

Unit ratio Default 1.386 Range At least 0

Outputs

IGC Required Shaft Power
About this output

Mass flow multiplied by selected-model specific work, before any separate motor, gearbox, or auxiliary loss allowance.

Unit kW
IGC Pressure Ratio
About this output

Dimensionless absolute discharge pressure divided by absolute inlet pressure.

Unit ratio
IGC Required Specific Work
About this output

Isentropic specific work divided by active efficiency; active efficiency is exactly one for the ideal branch.

Unit kJ/kg
Model Status
About this output

Returns actionable NOT VALID text for malformed inputs or unsupported arithmetic, CHECK text for no compression or zero flow, and OK otherwise. It is not an equipment rating or safety approval.

No unit declared
IGC Temperature Rise
About this output

Selected-model absolute temperature rise. Fahrenheit differences are nine fifths of the internal kelvin difference.

Unit K
IGC Isentropic Discharge Temperature
About this output

Ideal isentropic discharge temperature calculated from absolute inlet temperature and the pressure-ratio exponent.

Unit deg C
IGC Discharge Temperature
About this output

Isentropic discharge temperature in the ideal branch or inlet temperature plus isentropic temperature rise divided by entered efficiency in the adjusted branch.

Unit deg C
IGC Isentropic Shaft Power
About this output

Mass flow multiplied by isentropic specific work. It is zero at zero mass flow or unity pressure ratio.

Unit kW
IGC Model Basis
About this output

States whether results use the ideal isentropic relation alone or the user-entered isentropic-efficiency adjustment.

No unit declared
IGC Isentropic Specific Work
About this output

User-entered cp multiplied by the isentropic absolute-temperature rise, expressed per unit gas mass.

Unit kJ/kg

What it is

The Ideal Gas Compressor Power and Discharge Temperature Calculator works out what it takes to compress an ideal gas from one absolute pressure to another. It returns the pressure ratio, the isentropic discharge temperature, the selected-model discharge temperature, the temperature rise, the specific work on both the isentropic and the selected basis, and the shaft power at the mass flow you enter.

It runs on one of two bases. The ideal isentropic branch fixes the compressor efficiency at exactly one and reports the thermodynamic minimum. The efficiency-adjusted branch divides that work by an isentropic efficiency you enter, and puts the difference into the gas as heat, so the discharge temperature rises with it.

Every gas property is yours to supply. The specific heat at constant pressure and the heat capacity ratio gamma are both typed in, with no property lookup and no inference from gas identity. The shipped values are synthetic demonstration numbers, not table values.

It accepts SI metric entry in kilopascals absolute, degrees Celsius, kilograms per second and kilowatts, or U.S. customary entry in psia, degrees Fahrenheit, pounds mass per second and horsepower. Changing the selector relabels the fields; it does not convert numbers already entered.

Three limits matter before you use a number from it. Both pressures must be absolute, and a gauge entry is silently wrong. There is no compressibility factor anywhere in the model, so the gas is ideal throughout. And the power reported is gas-path shaft work only, with motor, gearbox and auxiliary losses outside it.

Methodology

Purpose and model boundary

This model estimates discharge temperature, specific work and shaft power for steady adiabatic compression of an ideal gas with user-entered constant heat capacity and heat-capacity ratio. It offers an ideal isentropic branch and an efficiency-adjusted branch. It is a thermodynamic screening model, not a compressor map, driver selection or equipment guarantee.

The spreadsheet is the calculation authority. The browser submits named inputs through the calculation service and renders the workbook's returned values, chart and status; it does not reproduce compressor formulas client-side.

Inputs and units

Input group Values used by the model
Model basis SI metric or US customary, and ideal isentropic or efficiency-adjusted compression.
State Inlet absolute pressure p1, discharge absolute pressure p2, and inlet temperature T1.
Gas and flow Mass flow , constant-pressure specific heat cp, and heat-capacity ratio γ.
Efficiency Isentropic efficiency η, visible and used only by the efficiency-adjusted branch.

Temperatures are converted to kelvin and US quantities to SI internally. Pressure inputs must be absolute, not gauge values.

Governing relationships

For pressure ratio PR = p2/p1 and exponent a = (γ − 1)/γ, the isentropic temperature is

T2s = T1 × PR^a.

The active efficiency is ηactive = 1 for the ideal branch and the entered η for the efficiency-adjusted branch. The selected discharge temperature, isentropic and required specific work, and powers are

  • T2 = T1 + (T2s − T1)/ηactive;
  • ws = cp(T2s − T1);
  • w = ws/ηactive;
  • Pisentropic = ṁws;
  • Prequired = ṁw.

The workbook's chart evaluates the same selected-model temperature expression at seven pressure-ratio points from 1 through the entered PR; it is not an equipment operating curve.

Calculation sequence

  1. Validate the unit and model choices, positive absolute pressures with p2 ≥ p1, inlet temperature above absolute zero, nonnegative mass flow, positive cp, γ > 1, and active efficiency in (0,1].
  2. Convert temperature, mass flow and heat capacity to the SI calculation basis.
  3. Calculate PR, the isentropic exponent, T2s, selected T2, specific work and power.
  4. Convert results to the selected display units.
  5. Check that public values, positivity relationships and chart points are finite and internally consistent.
  6. Return the model-basis label, temperature curve and ordered workbook status.

Outputs and interpretation

Primary outputs are selected discharge temperature, isentropic discharge temperature, required specific work and required shaft power. Details expose pressure ratio, temperature rise, isentropic work and power, and the active model basis. The ideal branch makes selected and isentropic results equal. The efficiency-adjusted branch increases temperature rise and work when η < 1.

Required shaft power is the modeled gas-path requirement. Motor input, gearbox, seal, bearing, cooling and auxiliary requirements need separate efficiencies and margins.

Validation and status logic

The workbook evaluates status in this order:

Condition Returned status
A visible selection, absolute pressure, temperature, gas property, flow or efficiency is outside the authored domain NOT VALID: correct visible selections, absolute pressures, temperature, gas properties, flow, or efficiency
A thermodynamic, converted or chart value is not finite or fails the protected numeric relationships NOT VALID: derived thermodynamic result exceeds the supported calculation range
p2 = p1 so PR = 1 CHECK: discharge pressure equals inlet pressure; no compression work is calculated
Mass flow is zero CHECK: zero mass flow produces zero shaft power
None of the preceding conditions applies OK

The equal-pressure check takes precedence over the zero-flow check when both conditions apply.

Assumptions and limitations

  • The gas is ideal; compression is steady and adiabatic; kinetic and potential energy changes are negligible.
  • Entered cp and γ are constant and representative of the whole temperature range. No gas composition or property lookup is supplied.
  • The adjusted branch treats η as one aggregate isentropic compressor efficiency.
  • Variable heat capacity, real-gas compressibility, condensation, chemical reaction, heat leakage, intercooling, aftercooling, multistage optimization and polytropic-map methods are outside scope.
  • No surge, choke, speed line, corrected flow, corrected speed, efficiency island or discharge-temperature limit is embedded.
  • Materials, lubrication, seals, vibration, critical speed, containment, relief, hazardous service and code compliance require separate review.

Restrictions and non-computing states

The model supports compression only: p2/p1 ≥ 1. Expansion, vacuum pumping below a pressure ratio of one, liquids and two-phase states are outside scope. Temperature must remain above absolute zero, γ must exceed one, and active efficiency must be greater than zero. A NOT VALID state supersedes displayed residues. Equal pressure and zero mass flow are deliberate computing boundaries with CHECK messages.

Errors and warnings

A rejected entry means the submission did not satisfy the published input rules. NOT VALID means the workbook refused the state; CHECK identifies a defined zero-work or zero-power boundary. Calculation-service failures are availability errors, not thermodynamic conclusions.

References

No compressor map, selection table, licensed gas property database or compressibility chart is reproduced. The calculator performs no property lookup: cp and the heat capacity ratio are user-entered, and the shipped values are synthetic demonstration numbers describing no particular gas. The workbook implements the ordinary textbook form of the ideal-gas isentropic compression relations, not the method of any single publication. The sources it cites are below.

Gas properties, compressibility factors, polytropic exponents and efficiencies, mechanical efficiencies, compressor maps, surge limits, allowable discharge temperatures and driver margins are not supplied here. Take them from a property source for your gas and from the manufacturer. Near the critical point or at high reduced pressure, redo the case with a real-gas equation of state.

Additional source notes migrated from Methodology

Gas-property justification, the compressor vendor's map and qualified thermodynamic and mechanical review govern real compressor selection.

Frequently asked questions

Do I enter gauge or absolute pressure?
Absolute, on both fields, because the isentropic relation is a ratio of absolute pressures, and the calculator cannot detect a gauge entry. On the shipped defaults, if 117.3 and 493.7 kilopascals had been gauge readings where the atmosphere is 101.325 kilopascals, the absolute values would be 218.625 and 595.025 and the ratio 2.7217 instead of 4.2089, with every downstream number too high and the status still OK. Add local atmospheric pressure before entering a gauge reading.
Does it account for real gas behaviour?
No. There is no compressibility factor input and no Z term in any formula, so the gas is ideal everywhere in the model. For a light gas at modest pressure and away from saturation that is a reasonable screening assumption. Near the critical point, at high reduced pressure, or for heavy hydrocarbons it is not: the compressibility factor departs from one, cp and gamma vary strongly along the compression path, and both the temperature rise and the work per unit mass can be materially wrong. The error is neither a fixed percentage nor reliably conservative, so it can fall either way. Redo such a case with a real-gas equation of state.
Why did changing the specific heat not change my discharge temperature?
Because cp does not appear in the temperature relation. The isentropic discharge temperature depends only on the inlet temperature, the pressure ratio and gamma; cp enters one step later, when the rise is turned into work. A cp error passes straight through to the specific work and the shaft power one for one and leaves both discharge temperatures untouched, so validating against a measured discharge temperature will catch a gamma error and will never catch a cp error.
Are cp and gamma checked against each other?
No. The calculator holds no gas constant and no property table, so it accepts any pair. Do the check yourself: for an ideal gas the implied gas constant is cp times gamma minus one, divided by gamma, or 0.2823 kilojoules per kilogram kelvin on the shipped defaults. There is also no upper bound on gamma. The shipped test corpus includes a case at gamma equal to 2, higher than any real gas, and the model returns OK.
Is the shaft power what my motor needs?
No. It is gas-path shaft work: mass flow times specific work, and nothing else. Mechanical, bearing, seal, gearbox and auxiliary losses sit outside it, and so does the motor. Standard practice separates gas power from brake power with a mechanical efficiency, and that factor does not exist here, so the driver load is above the figure printed.
Can I use this for a multistage compressor?
Not sensibly. There is no stage count, no interstage pressure and no intercooler, so the pressure ratio you enter is one uncooled compression to the final pressure. Real multistage machines intercool between stages, which lowers both the work and the discharge temperature. The efficiency offered is isentropic only, while multistage centrifugal practice works in polytropic terms because isentropic efficiency is not additive across stages.
What happens to the efficiency I entered on the ideal isentropic branch?
Nothing. The ideal branch fixes the active efficiency at exactly one, so the selected-model outputs equal the isentropic ones and the field is hidden. It is genuinely inert, not defaulted: the shipped corpus runs that branch at 0, 0.5 and 1 and returns identical numbers each time. The reverse also holds. An efficiency of exactly 1 on the efficiency-adjusted branch gives the ideal branch numbers, and only the model basis label tells them apart.
Why did every output come back as zero?
Because the inputs were refused. The declared field bounds are wider than the physics, so a value can pass the bound and still be rejected by the model, which returns NOT VALID and zeroes every output including the pressure ratio. Zero pressure, zero cp, a gamma at or below one, an inlet temperature at absolute zero, a discharge pressure below the inlet, or a zero efficiency while that field is visible will all do it. A separate gate does the same when a derived result overflows or underflows. Read the status line first.
This page is provided by LogicCommons for informational purposes only. Results are analysis outputs computed from the inputs you supply and are not engineering advice, a design, or a substitute for review by a licensed professional under the codes adopted where the work is built. Verify all inputs and results independently.

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